For random samples of size 180, suppose p = 0.09 for sample boxes converted to orders. Which check addresses whether p-hat is approximately normal?
- AOnly 180 > 30 must be checked.
- BUse sqrt(p(1-p))
- COnly p = 0.09 must be checked.
- D180(0.09) = 16.2 and 180(0.91) = 163.8correct
- EThe check requires exactly 10 observed successes.
Why D is correct
Check np and n(1-p): 180(0.09) = 16.2 and 180(0.91) = 163.8.
large-count check for sample boxes converted to orders: in the "For random samples of size 180, suppose p = 0.09 for sample boxes converted to orders. Which check addresses whether p-hat is approximately normal?" setting, especially sample boxes converted to orders; trial conversions, identify the sampling-distribution center, spread, and conditions before using a model. The professional check is to keep the values 180, 0.09, the sample proportion normal condition method, and the final answer choice aligned with Sampling Distributions.
Common mistakes. For the stem cue "For random samples of size one hundred eighty, suppose p = zero point zero nine for sample boxes converted to orders. Which check addresses whether p-hat is approximately normal?", a likely mistake is for proportions, expected success and failure counts are needed. Keep the calculation or conclusion tied to the original context.