Free AP Calculus AB practice questions
Calculus AB rewards a handful of moves done cleanly — differentiate, take a limit, integrate — and the AP exam keeps testing them. Try the AP-style samples below, see each one fully explained (including why every wrong choice is wrong), then keep practicing by unit. No credit card.

What the AP Calculus AB exam looks like
So you know what these samples are preparing you for. AP Calculus AB is a college-level introductory calculus course built on eight units — limits and continuity, differentiation, applications of the derivative, integration and accumulation of change, differential equations, and applications of integration.
Format and scoring can change year to year — always confirm current details on College Board — AP Calculus AB. The questions below are AP-style practice questions, not real or official AP exam questions.
AP-style practice questions
Three to warm up on. Pick an answer, submit, and read the full explanation — the correct choice, why the main traps fail, and the skill it tests.
Explanation — Correct: A
Differentiate term by term with the power rule: the derivative of x³ is 3x², and the derivative of −4x is −4. So f′(x) = 3x² − 4. Substitute x = 2: 3(2²) − 4 = 3(4) − 4 = 12 − 4 = 8.
Why C is wrong: 12 drops the −4 term entirely and reports only 3x² at x = 2. The −4x term still has a derivative (−4) — you can't ignore it.
Why B is wrong: 4 comes from mishandling the constant — for example computing 3·2 − 2 or otherwise losing the squaring in 3x². Apply the exponent first (3x²), then subtract 4.
Skill: differentiate a polynomial with the power rule term by term, then evaluate at the point. Don't drop the derivative of the linear term.
Explanation — Correct: B
Direct substitution gives 0/0, which is indeterminate — a signal to simplify, not to stop. Factor the numerator: x² − 9 = (x − 3)(x + 3). The (x − 3) cancels, leaving x + 3. Now substitute x = 3: 3 + 3 = 6.
Why C is wrong: "Does not exist" treats the zero in the denominator as a dead end. This is a removable discontinuity — the factor cancels, so the limit exists even though the function is undefined exactly at x = 3.
Why A is wrong: 0 assumes that 0/0 simply equals 0. The 0/0 form is indeterminate — it tells you nothing until you simplify.
Skill: when substitution yields 0/0, factor and cancel before re-substituting. Recognize a removable discontinuity instead of declaring the limit gone.
Explanation — Correct: C
Find an antiderivative of 2x: that's x² (since d/dx of x² is 2x). By the Fundamental Theorem, evaluate x² from 0 to 2: (2²) − (0²) = 4 − 0 = 4.
Why A is wrong: 2 comes from integrating to x instead of x² — that is, treating the antiderivative of 2x as if the 2 just stayed. The antiderivative of 2x is x², not 2x or x.
Why B is wrong: 8 uses 2² · 2 — squaring the bound and then multiplying by the coefficient again, double-counting the 2. Once you antidifferentiate to x², the coefficient is already built in.
Skill: antidifferentiate first, then plug the upper bound minus the lower bound. Confirm your antiderivative by differentiating it back.
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A full explanation on every answer
Not just an answer key — a four-part breakdown of why the right answer is right, why each wrong choice fails, the skill it tests, and the trap to avoid. You learn the reasoning, not just the letter.
Built to match the AP exam
Written to the format and difficulty of AP Calculus AB and aligned to the College Board's course framework, with calculator and no-calculator style items across all eight units.
Practice unit by unit
Work one unit at a time, then mix units the way the exam does, and let the mistake bank resurface what you miss so weak spots actually close.
Practice it, unit by unit.
Reading about calculus isn't the same as answering AP-style questions and learning from every miss. Start free and practice by unit.
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